Just 200-1=199 199+199=398 or -1+199=198 200+198=398 πΏ Edit : Thank you for 11 likes π
(2β’10^2)-10^0 + (2β’10^2)-10^0 2(10^2)-10^0 + 2(10^2)-10^0 4(10^2) - 2(10^0) 2^2(10^2) - 2(10^0) 2^2(10^2) - sqrt(2^2(10^2)) / 10 2^2(10^2) - (2^2(10^2))^Β½ / (2^2(10^2))^0β’10 2^2(10^2) - 2(10)/10 (2(10))^2 - 2 398
Yes , This question Came in JEE ADVANCED 2025 , getting DHOLAKPUR IIT CSE with this one ππ
The correct answer is b) 398 This question isnβt about BODMAS/BIDMAS (PEMDAS if youβre American), itβs about the β-β in -1 You can write the question like this (200)+(-1)+(199) So you can do: - (200-1)+199 = 199+199 = 398 or - 200+(-1+199) = 200+198 = 398 You will always get b)398 Hope that helps
99% will correct π―
200-1+199 200+198 398
According to bodmas am I right
200-1+199=(200-1)+199=199+199=2*199=398 200-(1+199)=200-200=0
BODMAS rule follows
For those who got it wrong, do 10000 push-ups and get your a*s back to elementary school for punishment
Should be 99.99999999999999999999999999% correct
Addition comes before subtraction tho?
in Indonesia, this multiplication answer is 0, not 398. because in Indonesia (+) and (-) are done (+) first then (-) and the answer is 0
as per BODMAS RULE: 200-1+199 =200-200 (AS Bracket Of Division,Multiplication,Addition and Subtraction. =0. or 200+198 = 398 I believe firat answer is correct as per bodmas rule,or 2nd one,as the answer is obvious
So simple bro 200 - 1 + 199 = 200 + 199 - 1 = 399 - 1 = 398
As I know this channel make higher level mathematics problem solving video but today , In this video the question is easier than any easier question.π π
bodmas is laughing in the corner ππππππ
200 - (1+199) =200-200 =0
It's 0 BC if 199+1=200 and 200-200 answer 0 everyone need brain π§ π§
@johnsmith-eh7wc